What is the sum of the measures of the interior angles of a regular polygon where a single exterior angle measures 72°?
more help please? I know the formula but how do i find out how many sides there are for n?
is it 252?
I did 180n - 72n = 108 and then 360 - 108 = 252?
Wait, I'm confused now too...@campbell_st care to clarify?
To solve for N i just did 108n - 72n = 108 .. then 360 - 108 = 252?
the sum of the exterior angles of a polygon is 360 there are 2 parts, the number of sides( or angles is found by) Number of sides(angles) n = 360/72 then the interior angle sum is Angle Sum = (n - 2)*180
Oh. I see...I misread the question :/
ooops n = number of sides
i thought so. so how do i solve for N first?
Yup. Following what ^ said, 360/72 = n. If so, what is n?
yes thats correct,,,,
So N = 5
Yes. Now, plug it in here: \[(n - 2)180\]
540?
Yes :)
ah, thankyou ! :D
np :)
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