Question

$6,000 for 6 years at 8½% compounded daily will grow to

Answer 1

Is this being interest per annum?
If it is then use
\[A=P(1+r)^n \]
\[A=6000(1+(0.085/365))^{6\times365}\]
\[A=6000(1.000232877)^{2190}\]
\[A=9991.1534\]
\[A=$9991.15\]