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MIT 18.06 Linear Algebra, Spring 2010 37 Online
OpenStudy (anonymous):

$6,000 for 6 years at 8½% compounded daily will grow to

OpenStudy (anonymous):

Is this being interest per annum? If it is then use \[A=P(1+r)^n \] \[A=6000(1+(0.085/365))^{6\times365}\] \[A=6000(1.000232877)^{2190}\] \[A=9991.1534\] \[A=$9991.15\]

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