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Mathematics 16 Online
OpenStudy (anonymous):

sqrt{192} + 9sqrt{12} + 2sqrt{108}

OpenStudy (ganpat):

1. 92 = 23 x 4 2. 12 = 4 x 3 3. 108 = 12 x 9 = 4 x 3 x 9 Now take the perfect square numbers outside.. 2 sq rt 23 + 9 * 2 sq rt 3 + 2 * 2*3 sq rt 3 2 sq rt 23 + 30 sq rt 3 2 (4.8) + 30 (1.7) = 60.6

OpenStudy (anonymous):

The answer is 38sqrt3, i'm trying to figure out the steps to get this answer

OpenStudy (ganpat):

ohkey.. its 192.. give me a sec.. i read it as 92..

OpenStudy (ganpat):

192 = 64 x 3 = 4 x 4 x 4 x 3 Take 2 x2 x2 outside of the root.. and resolve the above equation.. u will get ur answer..

OpenStudy (anonymous):

I'm not getting what your saying?

OpenStudy (ganpat):

ok i will write agian..

OpenStudy (ganpat):

1. 192 = 4 x 4 x 4 x 3 2. 12 = 4 x 3 3. 108 = 12 x 9 = 4 x 3 x 9 Now take the perfect square numbers outside.. 2 * 2 *2 sq rt 3 + 9 * 2 sq rt 3 + 2 * 2*3 sq rt 3 8 sq rt 3 + 30 sq rt 3 38 sq rt 3

OpenStudy (ganpat):

all u need is to factorise to lowest perfect square.. and take them out.. remaining numbers, let them under sq rt sign.. and solve further..

OpenStudy (anonymous):

Got it. Thanks!

OpenStudy (ganpat):

w.c

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