Question

LGBADERIVATIVE
\[\huge y = \sqrt{1+2e^{3x}}\]

Answer 1

\[y^2 = 1+2e^{3x}\]

Answer 2

no need for that

Answer 3

\[2yy\ = 1 + 6e^{3x}\]

Answer 4

i mean \[2yy' = 1 + 6e^{3x}\]

Answer 5

\[y' = \frac{1 + 6e^{3x}}{2\sqrt{1 + 2e^{3x}}}\]

Answer 6

right?

Answer 7

just apply tha chain rule:
\[ \Large y'=\frac{1}{2\sqrt{1+2e^{3x}}}2e^{3x}3 \]

Answer 8

no

Answer 9

no? why?

Answer 10

oh lol derivative of 1 is 0

Answer 11

\[\frac{d}{dx}[1]=0\]

Answer 12

*facepalm*

Answer 13

hail Zarkon!

Answer 14

i cant believe i make noobish mistakes :/ i really havent mastered derivatives lol

Answer 15

yeah to me..I know the derivative of 1 is 0 :)