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Mathematics 17 Online
OpenStudy (anonymous):

I need help with Question 34,24,59,60,25,30,31,27,28,46,47,48,52,53. Please explain how you arrived at the answer to. Thank You! http://www.eduweb.vic.gov.au/edulibrary/public/commrel/aboutschool/selectentry/mathspractice.pdf LINK

OpenStudy (helder_edwin):

are those the questions numbers?

OpenStudy (anonymous):

Yes

OpenStudy (helder_edwin):

for 34) you have two points: (0,4) and (6,-1) can u compute the slope?

OpenStudy (anonymous):

What do you mean. You can do anything to arrive at the answer I suppose.

OpenStudy (anonymous):

Can you skip to Question 25, I am most puzzled about that on. Apparently, Pythagorean theorem is involved.

OpenStudy (helder_edwin):

YES! the idea is work on the triangle AEG. apply pythagoras to compute EG first

OpenStudy (anonymous):

What happens after I worked out EG which is 10?

OpenStudy (helder_edwin):

now apply pythagoras again you have EG=10, AE=2 from the triangle AEG

OpenStudy (anonymous):

Its a bit confusing. Can you please explain?

OpenStudy (helder_edwin):

OK. you have a reactangle box wich means that all angles between the sides are 90º right?

OpenStudy (anonymous):

Yes

OpenStudy (helder_edwin):

now imagine you draw two lines: AG and EG the question is now what kind of triangle is AEG?

OpenStudy (anonymous):

Ok, what else? Thank you, I really appreciate this, this question I just am really stuck on! What's next? The next step?

OpenStudy (helder_edwin):

what kind of triangle is AEG?

OpenStudy (anonymous):

I don't know?

OpenStudy (helder_edwin):

what do u think is the measure of the angle between AE and the bottom of the box? the bottom of the box is the square EFGH.

OpenStudy (anonymous):

90^o?

OpenStudy (helder_edwin):

yes. if a triangle has one angle =90º, what is its name?

OpenStudy (anonymous):

for #24 \(x\) is the hypotenuse of a triangle where one side is \(5-3=2\) and the other side is 4 pythagoras give the hypotenuse as \[\sqrt{2^2+4^2}=\sqrt{20}=2\sqrt{5}\]

OpenStudy (anonymous):

The answer is A = 2/26 the answers say

OpenStudy (anonymous):

59 is pythagoras again solve \[(x+1)^2+(x+3)^2=(x+5)^2\] \[x^2+2x+1+x^2+6x+9=x^2+10x+25\] \[2x^2+8x+10=x^2+10x+25\] \[x^2-2x-15=0\]

OpenStudy (anonymous):

T

OpenStudy (helder_edwin):

yes u r right!

OpenStudy (anonymous):

Thanks everyone!

OpenStudy (anonymous):

you get \[(x-5)(x+3)=0\] so \(x=5\)

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

yw

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