Question

If x & y are positive with x-y=2 & xy=24, then\[\large{\frac{1}{x}+\frac{1}{y}=?}\]is equal to??
@Hero @ParthKohli @lgbasallote @apoorvk :)

Answer 1

Trial and error gives me that x = 6 and y = 4.

Answer 2

me too

Answer 3

You just have to find 1/6 + 1/4 :D

Answer 4

do you want legit explanation though lol...i can probably try...

Answer 5

6 x 4 = 24
6 - 4 = 2

Trial and error > Algebra in this case.

Answer 6

x = 2 + y

xy = 24

(2+y)y = 24

2y + y^2 = 24

y^2 + 2y - 24 = 0

(y+6)(y-4) = 0

y = - 6

y = 4

it says x and y are positive so take y = 4

Answer 7

now sub in to orig equation

Answer 8

x - 4 = 2
x = 2 + 4
x = 6

Answer 9

Answer:-\[\Huge{\color{green}{\frac{5}{12}}}\]

Answer 10

so then you do that thingy 1/6 + 1/4 = 10/24 = 5/12

Answer 11

thanx all f u:)

Answer 12

\[(\frac{1}{x}+\frac{1}{y})^2-(\frac{1}{x}-\frac{1}{y})^2=\frac{4}{xy}\\(\frac{1}{x}+\frac{1}{y})^2=(\frac{1}{x}-\frac{1}{y})^2+\frac{4}{xy}=(\frac{x-y}{xy})^2+\frac{4}{xy}\]