Question

Find the range and domain of \[\sqrt{9-x^2}\]

Answer 1

We cannot find the roots of negative terms..
So, terms inside the square root bracket must be equal to or greater than 0..

\[(9-x^2) > 0\]

So, try to find x..

Answer 2

I mean:
\[(9-x^2) \ge 0\]

Answer 3

Domain = [-3 , 3]

Answer 4

is that correct

Answer 5

Yes you are right..

Answer 6

then wat is the range

Answer 7

For range, let this expression equals:

\[y = \sqrt{9 - x^2}\]

Can you find change this expression in terms of x??

Answer 8

Square both the sides first and then find x in terms of y..

Answer 9

x =sqrt 9 - y^2

Answer 10

Again use the same technique terms inside the square root brackets must be greater than or equal to zero..

can you do it??
and then tell what you get as y??