Question

If $2000 is invested at an interest rate of 3.5% per year, compounded continuously, find the value of the investment after the given number of years:
a) 2 years
b) 4 years
c) 12 years

Answer 1

\[2000\times e^{2\times .035}\]

\[2000\times e^{4\times .035}\]

\[2000\times e^{12\times .035}\]

Answer 2

thanks

Answer 3

yw