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Physics 18 Online
OpenStudy (anonymous):

The motion of a particle is defined by the relation x = 1.5t^4 - 30t^2 + 5t + 10, where x and t are expressed in meters and seconds, respectively. Determine the position, the velocity, and the acceleration of the particle when t = 4 s.

OpenStudy (anonymous):

find the velocity and acceleration by taking the derivative, then substitute t = 4

OpenStudy (anonymous):

x(t) = 1.5t^4 - 30t^2 + 5t + 10 position x'(t) = 6t^3 - 60t + 5 velocity x''(t) = 18t^2 - 60 acceleration substitute t = 4 for each ~

OpenStudy (anonymous):

i got negative (-) 66 for the position. what does it mean?

OpenStudy (anonymous):

then it's going backward :s

OpenStudy (anonymous):

yea. :>

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