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The motion of a particle is defined by the relation x = 1.5t^4 - 30t^2 + 5t + 10, where x and t are expressed in meters and seconds, respectively. Determine the position, the velocity, and the acceleration of the particle when t = 4 s.
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find the velocity and acceleration by taking the derivative, then substitute t = 4
x(t) = 1.5t^4 - 30t^2 + 5t + 10 position x'(t) = 6t^3 - 60t + 5 velocity x''(t) = 18t^2 - 60 acceleration substitute t = 4 for each ~
i got negative (-) 66 for the position. what does it mean?
then it's going backward :s
yea. :>
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