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Mathematics 19 Online
OpenStudy (anonymous):

if tanA - tanB = x and cotB - CotA = y then cot(A-B)=?

mathslover (mathslover):

tan A = 1 / cotA right ?

OpenStudy (anonymous):

yes

mathslover (mathslover):

\[\huge{tanA=\frac{1}{cotA}}\] Ok also the same for tan B

OpenStudy (anonymous):

Cot(A-B) = cotA.CotB-1/(cotB - CotA)

mathslover (mathslover):

cot (A-B) = (cot A cot B + 1)/(cot B - cot A) ok !!!

mathslover (mathslover):

put cot B - cot A = y

mathslover (mathslover):

|dw:1341497660209:dw|

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