Mathematics
14 Online
OpenStudy (anonymous):
10 < –3x + 1
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mathslover (mathslover):
\[\huge{10 < -3x+1}\]
\[\huge{10-1 < -3x+1-1}\]
\[\huge{9 > -3x}\] remember whenever we multiply the sign of inequality changes
OpenStudy (anonymous):
ok
mathslover (mathslover):
* sorry i meant remember whenever we subtract the sign of inequality changes
mathslover (mathslover):
also whenever we divide by negative terms the sign of inequality also changes
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
thannks
mathslover (mathslover):
\[\huge{9 > -3x}\]
\[\huge{\frac{9}{-3}<\frac{-3x}{-3}}\] note here that the sign changed
\[\huge{-3<x}\]
mathslover (mathslover):
\[\huge{x>-3}\]
OpenStudy (anonymous):
2(x + 5) > 8x – 8
OpenStudy (anonymous):
how bout this
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mathslover (mathslover):
2(x+5) ? can u simplify this ?
OpenStudy (anonymous):
yes
u can do
2x =10
OpenStudy (anonymous):
i meant 2x+10
OpenStudy (anonymous):
2x+10 > 8x - 8
*8 +8
2x + 18 > 8x
is it right so far
OpenStudy (anonymous):
i accidently made a star thats a plus sign
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mathslover (mathslover):
oh very right can u do it further
OpenStudy (anonymous):
um let me try
OpenStudy (anonymous):
2x + 18 > 8x
do u put the xs on one side so
2x + -8x > -18
mathslover (mathslover):
dont forget to change the sign
mathslover (mathslover):
> this will convert into <
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OpenStudy (anonymous):
so 2x+-8x < -18
OpenStudy (anonymous):
then wat do i do
OpenStudy (anonymous):
oh wait i know
OpenStudy (anonymous):
u add the x's soo
-6x < -18
OpenStudy (anonymous):
right??
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mathslover (mathslover):
yes right !!!
mathslover (mathslover):
now divide both sides by -6
OpenStudy (anonymous):
then u do
x > -3
mathslover (mathslover):
ah great u r right again ... i was just going to check whether u changed that sign or not ... good
OpenStudy (anonymous):
yay thank u