Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2.

y = x2 + 4x − ___

Answer 1

You can plug in your vertex (-2,-16) for x and y and solve for the unknown number

Answer 2

so it will be -68?

Answer 3

No. I'll write it out

Answer 4

\[y=x^2+4x-A\]
A is the unknown. Plug in y=-16 and x=-2

Answer 5

Let me know if u need it further

Answer 6

y= -60 - A??

Answer 7

Plug in y=-16 and x=-2
\[-16=(-2)^2+4(-2)-A\]
-16=4-8-A
Add 'A' to both sides
-16+A=-4-A+A

'A' cancels on the right, so u have
A-16=-4

Add 16 to both sides
A-16+16=-4+16

16 npw cancels on the left, so u have
A=-4+16
A=12

Answer 8

so the answer is 12?

Answer 9

yes

Answer 10

thank youu

Answer 11

LOL Your welcome. You should try and write out the steps next time

Answer 12

alright ill remember too