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OpenStudy (anonymous):
den u'll get p^2(-5-2p)
OpenStudy (anonymous):
we cant substitute 3) in 1)
OpenStudy (anonymous):
=3/2
OpenStudy (anonymous):
ya itz upto u
OpenStudy (anonymous):
wait wait i dnt think u can do dat
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OpenStudy (anonymous):
lyk u get a value frm one equation nd hw can u substitute it in de same thing?
OpenStudy (anonymous):
yes thats what i was saying
OpenStudy (anonymous):
i mean 3) in 2)
OpenStudy (anonymous):
well i got de equation no: wrong bt wat i did was ryt
OpenStudy (anonymous):
den u can solve de quadraitic equation
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OpenStudy (anonymous):
the full sol. !
OpenStudy (anonymous):
can u tell me de value of p? lyk i'm already workin on sme problemz
OpenStudy (anonymous):
you mean the ans.?
OpenStudy (anonymous):
solve fr p...p^2(-5-2p)=3/2
OpenStudy (anonymous):
p is root we have to find p q and r..
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OpenStudy (anonymous):
if v get p, den (x-(p)) is a factor of the givn polynomial den v can divide de polynomila by (x-(p)) to get a quadratic polynimial den by splitting de middle term v get q nd r
OpenStudy (anonymous):
i don't want the ans. from synthetic division.
OpenStudy (anonymous):
bt v hav used de co efficient- zero relation ryt nd den only v r dividing...well dis is all i hav learnt
OpenStudy (anonymous):
i guess u hav to bump de question to get de ans: srry
OpenStudy (anonymous):
thanks
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OpenStudy (anonymous):
:)
OpenStudy (anonymous):
@ganeshie8 @mukushla @nitz Does any one of you knows Theory of Equations?
OpenStudy (jiteshmeghwal9):
do u mean proof of quadratic formula???
OpenStudy (anonymous):
no
OpenStudy (jiteshmeghwal9):
then wht???
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ok see this
Let's Suppose p=q
form
p+q+r= -b/a
pq+qr+pr= c/a
u have
2p+r=-5 -------->4p+2r=-10 -------->p+2r=-10-3p (I)
p^2+2pr=-23/4-------->p(p+2r)=-23/4 (II)
plug equation (I) in equation (II)
u will get
p(10+3p)=23/4 its a simple quadratic equation and it gives p=1/2 and p=-23/6
OpenStudy (anonymous):
roots : 1/2, 1/2 , -6
OpenStudy (anonymous):
Yeah I got it...
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OpenStudy (anonymous):
@shubham.bagrecha
p=1/2 and r=-5-2p=-6
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@mukushla why p=q=-23/6 and c=8/3 not taken??
OpenStudy (anonymous):
when p=1/2,c=-6
when p= -23/6, c=8/3
??
OpenStudy (anonymous):
check it with p^2 r=3/2
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