Question

evaluate e^(ln y)

Answer 1

e cancels ln

Answer 2

@Rainbow_Dash
We have
\[\large e^{\ln y}\]
We know \(\ln x=\log_e x\)
\[\large e^{\log_e y}\]
there is a logarithmic property
\[\large a^{\log_a b}=b\]
using that, we get
\[\large e^{\log_e y}=y\]

Answer 3

one way of looking at this is to let:\[\ln(y)=x\]this implies:\[y=e^x\tag{1}\]therefore:\[e^{\ln(y)}=e^x=y\text{ using(1)}\]