A Simple one: The domain of function f(x)=\(\sec^{-1} x\) is: a)(-1,1) b)R-[-1,1] c)R-(-1,1) d)[-1,1]
The question is equivalent to asking, what values can \(\sec{x}\) take? Can you reason this why it is so?
I guess its asking what values can x take? Isn't it?
I should have changed the \(x\) in my first post to avoid confusion. \(\sec^{-1}x\) is the inverse function of \(\sec{x}\). The domain of \(f(x) \) is the range of \(f^{-1}x\) and vice-versa. The question asks what value can \(x\) take so that \(\sec^{-1}x\) is defined. That is equivalent to asking \(y = sec^{-1}x\) or \(x = \sec{y}\) i.e. what values can \(\sec{y}\) attain
I think it should be [-1,1].. But it says the answer is R-(-1,1)
@FoolAroundMath
What values can \(\sec{x}\) attain ? \(\sec{x} = 1/\cos{x}\)
Thanks!
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