Please Help! Calculate the equilibrium constant for the following reaction at 298k: Zinc(s)+Cu^2-(aq)Zn^2-(aq)+Cu(s).

Question

Please Help!
Calculate the equilibrium constant for the following reaction at 298k: Zinc(s)+Cu^2-(aq)<=>Zn^2-(aq)+Cu(s).

cherylim23 · Answer

Are you sure the ions are Cu2- and Zn2-? They should both form cations seeing that they are metals.
Anyway, Kc = {[Cu]*[Zn2+]}/{[Zn]*[Cu2+]}
To find the numerical value of the equilibrium constant, more data needs to be given.
Hope this helps

anonymous · Answer

This is all the information that was given and the reaction is Zn(s)+Cu2+(aq)<=>Zn2+(aq)+Cu(s) Im sorry that was my mistake... Would you beable to help me now?

cherylim23 · Answer

Kc = {[Cu]*[Zn2+]}/{[Zn]*[Cu2+]}

K is always derived from [products]/[reactants]

vincent-lyon.fr · Answer

The question should read : "Give the expression of..." and not "Calculate..." which implies a numerical value.

Zinc and copper are solid metals so their activity is 1.

Hence: $K(T)=\Large \frac{[Zn^{2+}_{(aq)}]_{eq}}{[Cu^{2+}_{(aq)}]_{eq}}$

anonymous · Answer

@cherylim23 is that the answer? @Vincent_Lyon.Fr is that the answer?

cherylim23 · Answer

I made a mistake... didn't notice that it was a heterogeneous solution so Vincent is right.