Good explaing on how to find X :attached file.
x^2=45^2+45^2 x=sqrt(2)*45 This is according to pythagoras theorem. Also the figure is a square so all sides are equal x=63.64 approx
so basically ur timesing the givin number twice and adding them to gether to get the answer?
according to pythagoras theorem in a right angled triangle base^2+height^2=hypotenuse^2 used this to find x
the given figure is a square with side 45. diagonal of a square = side*sqrt(2)
i got 4050?
u should get 63.64
do i 4050^2 ?
you have to square root your answer to get x. you have found value of x^2
how do i put tht in the calcutaor?
just write 4050 and press the button that looks like
\[\sqrt{}\]
u should have a root signed button. type in 4050 and press it.
ohhh okay see i thought you ment exponent
who do i give the medal to . you guys are really helpful thank you very much :)
oh and my name is alyssa lol thank you on the help on this one @Vaidehi09 & @ProgramGuru
the medal dosent matter. What matters is that you have understood the problem and successfully solved it!
and also that u'll be able to solve such probs in future. well said @ProgramGuru.
since the bisect of square produce two triangle with 45 degree you can use the formula sin theta= perpendicular/ hypotenuse so sin 45=45/ hypotenuse sin 45= 0.71 so 0.71=45/ hypotenuse or hypotenuse= 45/0.71 hypotenuse = 63.38
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