Question

cos13+sin13/cos13-sin13 = tanA find A=?

Answer 1

two equal signs?

Answer 2

WELCOME TO OPEN STUDY

Answer 3

\[\frac{\cos 13 + \sin 13}{\cos 13 - \sin 13} = \tan A?\]

Answer 4

I think there is one equal sign..
next sign is for finding..

Answer 5

If we are just asked to find A then:

\[A = \tan^{-1} (\frac{\cos13 + \sin13}{\cos13 - \sin13})\]

Answer 6

i think it's using trig identities...

Answer 7

otherwise that would be too easy...just a job for a calculator lol

Answer 8

without the use of calculator

Answer 9

\[\frac{tanA + tanB}{1 - tanA .tanB} = \tan(A + B)\]

Answer 10

\[A = \tan^{-1} (\frac{1 + \tan13}{1 - \tan13})\]

\[A = \tan^{-1} (\frac{\tan45 + \tan13}{1 - \tan45.\tan13}) \implies \tan^{-1}(\tan(45 + 13)) \implies A = 58\]

Answer 11

thankyou

Answer 12

Welcome dear..

Answer 13

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