examine the differentiability of the function f(x)=x^2+2 at x=2
limit of f(x) at x=2 exists and function is continuous so f(x) is differentiable at x=2
it is differentiable at x=2 f\(x)=2x
f'(x)=2x f'(2)=4
it is polynomial and polynomials are always continuous and (so limit exits) so it means this is differentiable at x=2 f'(x)=2x f'(2)=2(2)=4
but who i know if differentible or not there is some method to prove
yes there is for example f(x)=|x| is not differentiable at x=0 and the function f(x)=x^(2/3) is not differentiable at x=0 because take its derivative f'(x)=2/3/(x^1/3) if i put x=0 then the function gets undefined if limit exists then most probably derivative exists
a function is differentiable if the limit at that point from left hand and right hand is same and exists.
thx sami
i think i want to solve by ur way @munish
a differentiable function is a function whose derivative exists at each point in its domain. if x0 is a point in the domain of a function ƒ, then ƒ is said to be differentiable at x0 if the derivative ƒ′(x0) is defined. This means that the graph of ƒ has a non-vertical tangent line at the point (x0, ƒ(x0)), and therefore cannot have a break, bend, or cusp at this point. and rest is same as @sami-21 told
okay thank u @annas and @sami-21
as i said no thanks to friends friends are for help :)
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