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Mathematics 19 Online
OpenStudy (anonymous):

You are given the value of a product in 2004 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = 0 represent 2000.) 156$, with $4.50 increase per year

OpenStudy (anonymous):

Just tell me if I'm right? I got 178.5 dollars

Parth (parthkohli):

Yep. That is correct.

Parth (parthkohli):

But, that question also tells you to make an equation.

OpenStudy (amistre64):

slope = rate of change of a linear equatio

OpenStudy (phi):

Write a linear equation the answer is not a single number. Use point slope to find the equation

Parth (parthkohli):

The slope is already given, btw. @schmidtdancer

OpenStudy (anonymous):

Oh really... how would I make an equation??

OpenStudy (anonymous):

slope = 4.5 y intercept = 156 - 4.5*4

OpenStudy (anonymous):

note that t=0 starts at 2000, and the 156 price given is in 2004 !!

OpenStudy (anonymous):

so the equation comes to y = 4.5x + 138

OpenStudy (anonymous):

Ok are u sure about that?^^ and is my 178.5 right?

OpenStudy (anonymous):

do you agree @ParthKohli

OpenStudy (anonymous):

?

OpenStudy (anonymous):

178.5 is the price in year (2004+5) = 2009 :) changing variables according to question, the equation is V = 4.5t + 138

OpenStudy (anonymous):

thanks so much

OpenStudy (anonymous):

yw :D

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