Question

can anyone show me how to do?
degree 3; zeros 3;-i;8+i?

Answer 1

is it really zeros of \(\{3,-i,8+i\}\)?

Answer 2

because if so your polynomial will have complex coefficients, not real ones
if it had real ones they have to come in conjugate pairs, like \(\{i,-i\}\) and \(\{8+i,8-i\}\)

Answer 3

I need to find all remaining zeros

Answer 4

if you do you will have 5 zeros, so it will not be a polynomial of degree 3, it will be a polynomial of degree 5

Answer 5

complex zeros of real polynomials come in conjugate pairs,
if \(a+bi\) is a zero, then so is \(a-bi\)

Answer 6

in your case if \(-i\) is a zero then so is \(i\) and if \(8+i\) is a zero then so is \(8-i\)

Answer 7

but as i said, the polynomial will be degree 5 not 3

Answer 8

ok what if I would have degree 3; zeros 8, 8-i?

Answer 9

Actually the equation has complex cofficients .