what are the solutions of 2x2 + 13x + 6 = 0.

Question

anonymous · Answer

its 2x^2 by the way

anonymous · Answer

Common factoring: first, multiply the first and third term coefficients: 
That is, 2x6 =12 
Now, find two numbers that multiply to 12 and add to 13: that is 12 and 1, because 12x1 = 12 and 12 + 1 =13.

Then, as follows:
2x^2 + 12x + x + 6

Then, factor:
2x (x+6) + (x+6)
(2x+1) (x+6) = 0
Now, you can find both of these values @ 0:

2x+1 = 0
2x = 1
x = 1/2

x+6 = 0
x = -6

jiteshmeghwal9 · Answer

$$2x^2+12x+x+6=0$$$$2x(x+6)+(x+6)=0$$$$(2x+1)(x+6)=0$$so$$2x+1=0$$$$2x=-1$$$$x={-1 \over 2}$$&$$x+6=0$$$$x=-6$$

anonymous · Answer

Yeah, correct my first part: 2x+1=0, then 2x=-1, so it's -1/2, Sorry!

anonymous · Answer

OHHH its the factoring, i did wrong thanks so much guys

anonymous · Answer

OHHH its the factoring, i did wrong thanks so much guys

anonymous · Answer

2x^2+13x+6=0
break the middle term i.e 13x