Question

Want to check my answer: What is the inverse laplace transform of 2/(s^2+4)?

Answer 1

you want just the answer ?

Answer 2

is it sin(2t)/2?

Answer 3

so close ! i think 1/2(s^2+4) -----> sin(2t)

Answer 4

AH! I forgot to multiply back in the 2, right?

Answer 5

you have 2 in the denominator......you have to multiply by 4 ! no ?

Answer 6

is it not a hyperbolic sin formula?

Answer 7

\[(1/2)*1/(s^2+4)------>\sin(2t)\]

Answer 8

i believe it is L^(-1){1/(s^2-B^2} = (sinh(Bt))/B

Answer 9

sorry, i made a mistake !

Answer 10

I looked again, maybe just a sin, not sinh

Answer 11

yeah yeaaah your right ! it's sin(2t)

Answer 12

sorryy , for waisting your time !

Answer 13

awesome, thank you

Answer 14

not at all

Answer 15

learning experiences

Answer 16

yeaah ! Good luck !