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Mathematics 19 Online
OpenStudy (anonymous):

how you would factor 8x^6 – 56x^3 + 98. could you walk me trough the solving process step by step

OpenStudy (anonymous):

Alright. First factor out the GCF. 2(4x^6 - 28x^2 + 49) Do you recognize how 4x^6 - 28x^2 + 49 is a perfect square?

OpenStudy (anonymous):

the gcf is 2?

OpenStudy (anonymous):

Yeah. After that, do you see how it forms a perfect square pattern though?

OpenStudy (anonymous):

no its kinda hard bc of the ^s

OpenStudy (anonymous):

but im trying to break them down

OpenStudy (anonymous):

\[2(4x^{6} - 28x^{3} + 49)\]

OpenStudy (anonymous):

\[2(4x ^{6}-28x ^{2}+49)\]

OpenStudy (anonymous):

dang lol

OpenStudy (anonymous):

ok what is that again?

OpenStudy (anonymous):

perfect square

OpenStudy (anonymous):

A perfect square trinomial looks like this. \[(a - b)^{2} = a^{2} - 2ab + b^{2}\]

OpenStudy (anonymous):

oooo ok i gotcha, so what is the next step after you realize its a perfect square

OpenStudy (anonymous):

You factor it based on that fact. \[2(4x^{6} - 28x^{3} + 49) = 2(2x^{3} - 7)(2x^{3} - 7)\]That's the farthest you can go I think at this point.

OpenStudy (anonymous):

okay gotcha well dang that prob wasnt a good one to choose since the other problems dont have perfect square

OpenStudy (anonymous):

Yeah. lol

OpenStudy (anonymous):

5x3 – 35x2 + 60x. would that be a good one?

OpenStudy (anonymous):

there

OpenStudy (anonymous):

we got to 2(2x3−7)(2x3−7)

OpenStudy (anonymous):

Do you need to factor x^3 – 35x^2 + 60x?

OpenStudy (anonymous):

yes but i need to know how to get the factors of the last problem

OpenStudy (anonymous):

You mean 2(2x3−7)(2x3−7)?

OpenStudy (anonymous):

yes***

OpenStudy (anonymous):

The factors are 2 and 2x^3 - 7

OpenStudy (anonymous):

Or you might have to say 2 and 2x^3 - 7 multiplicity 2.

OpenStudy (anonymous):

what does that mean

OpenStudy (anonymous):

THose are the factors.

OpenStudy (anonymous):

ty do you wan me to open a new window for the other problem

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