Logb = (5^5 7^2 / 2^6) what is/are the solution/s? Click attachments for better problem outlook
\(\huge Log_b x = \frac{5^5 7^2}{2^6}\) \(\huge => x = b^{\frac{5^5 7^2}{2^6}}\)
what if there's no equal sign there? will we able to get the solution for it?
thank you by the way :D
then it makes more sense... i have assumed x in the empty space before equal sign lol. u see that eh ?
ahaha sorry for that, i copied a wrong one :)) sorry again
\(\huge Log_b\frac{5^5 7^2}{2^6}\) \(\huge Log_b5^5 7^2 - Log_b 2^6\) \(\huge Log_b5^5 + Log_b 7^2 - Log_b 2^6\) \(\huge 5.Log_b5 + 5 . Log_b 7 - 6 . Log_b 2\)
we have used addition & subtraction properties of log, and made the simple expression more complicated hehe :D
np :))
but in the choices it has numbers like 69 like that
mhmm
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