Question

y' + y = y^-2 using bernoulli's equation

Answer 1

bernoulli's equation says that

\[u=y^{1-n}\]

Answer 2

go on

Answer 3

\[u=y^{1-2}\]

\[u=y^{-1}\]

Answer 4

solve for y and take the derivative in respects to x (using the chain rule)

Answer 5

\[\frac{dy}{dx}=\frac{du}{dx}*\frac{dy}{du}\]

Answer 6

can you do this and tell me what you et

Answer 7

is the answer must be y^3 = 1+Ce^-3x??

Answer 8

in really not good at ODE..i just need help..

Answer 9

so did you use the above and substitute in? what did you get for your linear equation in u

Answer 10

i did not sole that i just guess that from the choices

Answer 11

what do you think is the right solution for that?

Answer 12

i can't just give you the answer. You need to do some of the work also. I'm sorry

Answer 13

if you give me the right answer i can review for that and know what is wrong from my answer.

Answer 14

sorry but i think
\[u=y^{1-(-2)}=y^3\]

Answer 15

so your saying that it is y^3 = 1+Ce^-2x??

Answer 16

ah yes that is correct @mukushla