y' + y = y^-2 using bernoulli's equation

Question

anonymous · Answer

bernoulli's equation says that

$$u=y^{1-n}$$

anonymous · Answer

go on

anonymous · Answer

$$u=y^{1-2}$$

$$u=y^{-1}$$

anonymous · Answer

solve for y and take the derivative in respects to x (using the chain rule)

anonymous · Answer

$$\frac{dy}{dx}=\frac{du}{dx}*\frac{dy}{du}$$

anonymous · Answer

can you do this and tell me what you et

anonymous · Answer

is the answer must be y^3 = 1+Ce^-3x??

anonymous · Answer

in really not good at ODE..i just need help..

anonymous · Answer

so did you use the above and substitute in? what did you get for your linear equation in u

anonymous · Answer

i did not sole that i just guess that from the choices

anonymous · Answer

what do you think is the right solution for that?

anonymous · Answer

i can't just give you the answer. You need to do some of the work also. I'm sorry

anonymous · Answer

if you give me the right answer i can review for that and know what is wrong from my answer.

anonymous · Answer

sorry but i think 
$$u=y^{1-(-2)}=y^3$$

anonymous · Answer

so your saying that it is y^3 = 1+Ce^-2x??

anonymous · Answer

ah yes that is correct @mukushla