Question

what is the vertex of the function y=x^2-4x+3/

Answer 1

@agentx5 can you help me

Answer 2

vertex for of this type of equation:
\[y=a(x-h)^{2}+k\]
where (h,k) is the vertex. So compleat the square to find this form and you got it

Answer 3

vertex form*

Answer 4

y=x^2-2.2x+3+1-1
y=x^2-2.2.x+2^2-1
y+1=(x-2)^2
y=(x-2)^2-1
centre is (2,0)

Answer 5

jasminecrump18 do u understood

Answer 6

First of all I would take a look at factoring that quadratic polynomial, it turns into:
y=(x-3)(x-1)
Solve for x when y=0 to find the roots, +3 and +1 in this case:



The standard form is:
\(y = ax^2 + bx + c\)

\(y = a(x – h)(x – h) + k\)
\(y = ax^2 – 2ahx + ah^2 + k\)

The vertex form is:
\(y = a(x – h)^2 + k\)
Where (h,k) is your vertex's coordinates!

So for a, b, c... the x-coordinate is \(-\huge \frac{b}{2a}\)

To find the y-coordinate you need to plug back in.




PS: Grr @myko