The hypotenuse of a 30°- 60°- 90° right triangle measures 22 cm. What are the lengths of the longer leg and shorter leg?
sin theta - p/h
The shorter leg is half the hypotenuse. The longer leg is just \(\sqrt3\) multiplied to the shorter leg.
So if like the shorter leg is 8, then hypotenuse = 16 and longer leg = \(8\sqrt3\)
Just gotta put \(\sqrt3\) after the shorter leg :3
More examples: SL = Shorter leg LL = Longer leg SL = 3, LL = \(3\sqrt3\) SL = 4, LL = \(4\sqrt4\) You get the point.
so it'd be 11sqrt(3) for shorter leg
11sqrt(3) for the longer leg*
This is applicable to ALL \(30-60-90\) triangles.
Oh so the longer leg would be the 11sqrt(3)
Yay
but how do I find shorter leg again?
half the hypotenuse
@Ledah Sir, are you there?
half the hypotenuse would be 11.
Yep. You got it!
If you got the shorter leg, then you get the longer leg by putting that \(\sqrt3\) in front, and get the hypotenuse by multiplying 2 to the shorter leg.
If you got the longer leg, then remove \(\sqrt3\) from that, and you got the shorter leg. Multiply two to that for getting the hypotenuse.
okay wait wait wait. remove the sqrt3 from the longer leg and do what?
Hmm. Examples will do good. If the longer leg is \(9\sqrt3\), then the shorter leg is \(9\cancel{\sqrt3} = 9\)
The hypotenuse will then be \(2 \times SL = 2 \times 9 = 18\)
meaning it would be 2*11= I get that first part but where are the second set of numbers coming from. o3o
WUT
You haz all the sides
:O
Hypotenuse = 22 SL = 22/2 = 11 LL = 11sqrt3
Didn't you note that down?
oh yeah I did. :x I just like lost it xD
lolol
Thanks xD
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