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Mathematics 6 Online
OpenStudy (anonymous):

someone please help

OpenStudy (anonymous):

wats ur qstn ?

OpenStudy (lgbasallote):

we're here for you. aal izz well

OpenStudy (anonymous):

that is why I am here for

OpenStudy (anonymous):

describe how to find the multiplier for an exponential growth rate of 15%

OpenStudy (lgbasallote):

do you mean the growth constant?

OpenStudy (anonymous):

15/100

OpenStudy (anonymous):

0.15

OpenStudy (anonymous):

my mistake

OpenStudy (lgbasallote):

@chikitagee what's the whole problem? is the time given? we cant solve it without time

OpenStudy (anonymous):

15/100 +1 = 1.15

OpenStudy (anonymous):

it just says to describe how to find the multiplier for an exponential growth rate of 15% and describe how to find the multiplier for a rate of decay of 15%

OpenStudy (anonymous):

for growth, 15/100+1 = 1.15 for decay, 1- 15/100 =0.85

OpenStudy (lgbasallote):

oh wait i dont think time is needed. it's already implicity given when time = 1 then the population would be x = x_0 + 0.15 x_0 where x_0 is the initial population now use the formula \[\ln (\frac{x_0}{x}) = kt\] like i said x = x_0 + 0.15 x_0 and t = 1 \[\ln (\frac{x_0}{x_0 - 0.15 x_0}) = k\] \[\ln (\frac{\cancel{x_0}}{\cancel{x_0}(1 - 0.15)}) = k\] \[k = \ln (\frac{1}{1- 0.15})\] does that help?

mathslover (mathslover):

I think lgba has got the best soln .. gr8 lgba @chikitagee got it ?

OpenStudy (anonymous):

yea it does thanks everyone

OpenStudy (lgbasallote):

<tips imaginary hat>

OpenStudy (lgbasallote):

coincidentally...i have to leave now and get home so bye!

mathslover (mathslover):

\[\Huge{<\textbf{tips hat}>}\]

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