Question

\[\huge 2^{2x+2}-a*2^{x+2}+5-4a \ge 0 \forall x \epsilon R \] is true. then find "a".

Answer 1

@nitz

Answer 2

Let:

\[\large 2^{x+2} = y\]

\[y^2 - ay + (5-4a) \ge 5\]

Answer 3

No, the question is wrong..

Answer 4

\[y^2 - ay + (5-4a) \ge 0\]

Answer 5

oh sorry
question is right and @waterineyes y^2/4 -ay+(5-4a) .....
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Answer 6

If the question is right then you are also right.. @mukushla benim yoldashim..

Answer 7

go on

Answer 8

Then we will get:

\[y^2 - 4ay + (20 - 16a) \ge 0\]

Answer 9

Find Discriminant from here..

Answer 10

Or I am wrong???

Answer 11

quite right

Answer 12

\(D = b^2 - 4ac\)

\(D = 16a^2 - 80 + 64a\)

\(D = 80a - 80\)

Answer 13

D=16(a^2+4a-5)
be carefull

Answer 14

Oh sorry sorry..

Answer 15

\[D = 16a^2 - 80 + 64a\]

Take 16 common:

\[D = 16(a^2 +4a -5)\]

Answer 16

We have to solve this equation or not??

Answer 17

\[D = 16(a+5)(a-1)\]

Answer 18

we have to solve \( D \le 0 \)

Answer 19

Yes..

\[(a+5)(a-1) \le 0\]

Answer 20

a = 1 and a = -5 is it??

Answer 21

Or, a < 1 and a > -5??

Answer 22

\[-5 \le a \le 1\]