Question

tan 49 deg = 19/x

Answer 1

@BTaylor

Answer 2

i can't find the answer for x :(

Answer 3

\(\large \tan \theta = \huge \frac{opposite}{adjacent} \)

Answer 4

Algebra tricks... (writes)

Answer 5

\[\tan 49^o = \frac{19}{x}\]
\[x\tan 49^o = 19\]
\[x = \frac{19}{\tan 49^o}\]

Answer 6

16.51?

Answer 7

@Liltico did u get it?

Answer 8

16.52

Answer 9

@Liltico is correct.

Answer 10

thanks agent

Answer 11

You got a typo I see @Qibtiya , it's 49\(^o\) not 14\(^o\)

Answer 12

oh i thought that tan is 14 degree instide of 49
tan 49=1.150
tan 49=19/x
or
x=19/tan 49
put the value of tan 14
x=19/1.150
x=16.51

Answer 13

@agentx5 yeah got it