Find the inverse of the one-to-one function. f(x) = 2x + 5/7 Is this one y=7y+5/2
oops that is suppose to be y=7x+5/2
solve implicite for x and then replace x by y, this gives you the inverse function
So is that what I did my getting y=7x + 5 /2
\[ y=2x+\frac{5}{7} \\ \therefore x = \frac{1}{2}\left(y-\frac{5}{7}\right)\]
\[ f(\bar{x})=\frac{1}{2}\left(x-\frac{5}{7}\right)\]
but my choice look like this a. f^-1(x) = 7/2x+5 b. f^-1(x) = 7 / 2x -5 c. f^-1(x) = 7x + 5 /2 d. f^-1(x) = 7x - 5 / 2
http://www.wolframalpha.com/input/?i=inverse+function+of+y%3D7x%2B%285%2F2%29
Sorry, but in this case I can't help you, since I don't find any of the solutions above representing a inverse function of the one you have posted
See that is what is confusing me because the answer I got to didn't match my choices
thanks any ways I will call the school tomorrow about this one
alright, you're welcome
Keep in mind that you can verify your answer always for yourself, by drawing it in a xy-Coordinate system, it should be mirrored at y=x, which is the case for the function we have.
okay thanks
and also f(x) when you replace it by the inverse function for the original equation should be x, which is also the case for the function we have.
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