The center of mass of a 0.2 kg (non-uniform) meter stick is located at its 46-cm mark. What is the magnitude of the torque (in Nm) due to gravity if it is supported at the 26-cm mark? (Use g = 9.79 m/s2).

Question

The center of mass of a 0.2 kg (non-uniform) meter stick is located at its 46-cm mark.  What is the magnitude of the torque (in Nm) due to gravity if it is supported at the 26-cm mark? (Use g = 9.79 m/s2).

4n1m0s1ty · Answer

So here's your stick:

---------26cm----------------------------46cm-------------------
               fulcrum                                             center of mass
 
where are the forces acting on this system?

anonymous · Answer

Torque=Force*Distance
Weight=m*g
Distance=46-26
Force=?

anonymous · Answer

Remember to put the distance in m, so distance=0.2m