Question

The solution to x = log91.43 is approximately 1.6. true or false?

Answer 1

can't u use a calculator to verify?

Answer 2

no :(

Answer 3

@iceywheniplease7 , what part are you having trouble with?

Answer 4

all of i dont understand the whole log solution thing and stuff

Answer 5

try this...
\(\large 10^{1.6} \)
if that gets you reasonably close to 91.43, then i'd say yes.... if not, then no...

Answer 6

Okay. Do you know what an exponent is?

Answer 7

yes

Answer 8

idt thats right.... haha

Answer 9

Well, a logarithm is basically the opposite of an exponent.

Answer 10

oh?

Answer 11

Well, besides their nasty name, they are really quite simple.

Answer 12

\(x^n=\{x*x*x\}\text{n-times}\) right?

Answer 13

Or, 4^13=4*4*4*4*4*4*4*4*4*4*4*4*4*4

Answer 14

A log is like the opposite of an exponent. If an exponent was multiplication, a log would mean division.

Answer 15

\(\log_44^{13}=13\)

Answer 16

or, \(\log_24^{13}=\log_22^{2^{13}}=\log_22^{26}=26\)

Answer 17

how bout \(\log_{10}13\)? well, we are basically asking this question.
\(10^x=13\)
Well, it turns out to be nasty. In fact, we can't do this by hand. Luckily, we can do it by calculator. I got something around
1.1139
If you try 10^(1.1139), you'll get a number close to 13. That is what a logarithm is.