Question

(x-3)(x-3)=27 solve using an appropriate technique??? help please

Answer 1

x^2-3x-3x+9=27 after solving lhs
x^2-6x+9=27
x^2-6x-18=0
solve it further by yourself

Answer 2

\[(x-3)^{2}=27\]
\[x-3=\pm \sqrt{27}\]
\[x-3=\sqrt{27} \] and
\[x-3=-\sqrt{27}\]\[x=\sqrt{27}+3\] and \[x=-\sqrt{27}+3\]

Answer 3

as \[\sqrt{27}=3\sqrt{3}\]
therfore,\[x=3\sqrt{3}+3 \] and \[x=-3\sqrt{3}+3\]