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Mathematics 8 Online
OpenStudy (anonymous):

With respect to the origin O, the points A and B have position vectors given by −−→ OA = i + 2j + 2k and −−→ OB = 3i + 4j. The point P lies on the line AB and OP is perpendicular to AB. 1. Find a vector equation for the line AB. 2. Find the position vector of P. 3. Find the equation of the plane which contains AB and which is perpendicular to the plane OAB,

OpenStudy (anonymous):

yes, i am very weak in vectors.

OpenStudy (anonymous):

ab=ob-oa=2i+2j+2k

OpenStudy (anonymous):

you just found the direction vector ! @sai1234

OpenStudy (cwrw238):

join the club! vectors is not my strong point other if i remember rightly r = a + bd where a is a known position vector of point on the line, d = direction vector and b is a constant

OpenStudy (phi):

|dw:1342804456246:dw|

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