Question

Can anyone help me please?
In a right triangle: The altitude=y The base=y The hypotenuse=3 Find the value of y.

Answer 1

Use Pythagorean theorem. y^2+y^2=3^2

Answer 2

So what is the answer? @allank \[\sqrt{y^4}= \sqrt{9}\]

Answer 3

sqrt(2y^2)=3

Answer 4

y^2+y^2=3^2
that becomes 2(y^2)=9
then y^2=(9/2)
thus y=sqrt(9/2)

Answer 5

@timo86m I don't see that answer on my hw...
a. y=2sqrt3/4
b.y=3sqrt2/4
c.y=sqrt6/2
d.y=3sqrt2/2

Answer 6

it is not completed lol just a hint

Answer 7

y = (3/2)*sqrt(2)

Answer 8

d

Answer 9

@timo86m SO my answer should be d?

Answer 10

yeah but is it over 2 or 4?@timo86m

Answer 11

y = (3/2)*sqrt(2)

Answer 12

\[y=3\sqrt{2}/2\]

Answer 13

it d :)