Question

Factor completely p4 – 81

Answer 1

I dont even get it, what times 81 twice then adds to p^4?

Answer 2

write it as
(p^2)^2 - (9)^2

Answer 3

now apply rule for difference of 2 squares
a^2 - b^2 = (a - b)(a + b)

Answer 4

do you follow that?

Answer 5

(p – 3)^2(p + 3)^2

Answer 6

yeah, thats my answer than right

Answer 7

a = p^2 and b = 9

Answer 8

(p^2)^2 - (9)^2 = (p^2 - 9)(p^2 + 9)

- now you apply rule to p^2 - 9

Answer 9

You can also brute force this if you like: