Question

calc 3 help

use the double integral to find the volume of the solid in the first octant bounded above by paraboloid z=x^2+3y^2, below by the plane z=0, laterally by y=x^2 and y=x

Answer 1

I simply used o to 1 for dx and x^2 to x for dy, integrated and got 11/70

can someone check my answer? That would be awesome

Answer 2

\[
\int _0^1\int
_{x^2}^x\left(x^2+3
y^2\right)dydx=\frac{11}{70
}
\]

Answer 3

Your answer is right.