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Mathematics 15 Online
OpenStudy (anonymous):

Solve. x2 – 10x = –13

OpenStudy (anonymous):

why did you close the previous problem?

OpenStudy (anonymous):

First you have to set it equal to zero

OpenStudy (anonymous):

Again, you must move the 13 over and this can be factored into a product of two binomials. The behavior will be apparent when you set each equal to 0.

OpenStudy (anonymous):

can some one show me the quad form and the abc

OpenStudy (anonymous):

Simply add the 13 on both sides and it will be in proper form.

OpenStudy (anonymous):

did you do what @Lulu and @qpHalcy0n said? you need to get your equation in standard form: \(\large ax^2+bx+x=0 \) so you can identify your coefficients to use in the quadratic formula...

OpenStudy (anonymous):

omg this is so confusing

OpenStudy (anonymous):

i'm assuming that's what you meant by doing it the "abc" way...

OpenStudy (anonymous):

idk i guess ill just have to figure it out later i need to give my brain a break

OpenStudy (anonymous):

i meant \(\large ax^2+bx+c=0 \)

OpenStudy (anonymous):

5 ± 2 5 ± 5 ± 2 5 ± 3

OpenStudy (anonymous):

thats not one of the choices

OpenStudy (anonymous):

I believe the last problem you posted could be factored into a product of two binomials. This one does not factor that nicely. Sorry. So disregard that. ...Or I was thinking of another problem.

OpenStudy (anonymous):

5 ± 2sqrt3 5 ± sqrt38 5 ± 2sqrt2 5 ± 3sqrt2

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