Solve. x2 – 10x = –13
why did you close the previous problem?
First you have to set it equal to zero
Again, you must move the 13 over and this can be factored into a product of two binomials. The behavior will be apparent when you set each equal to 0.
can some one show me the quad form and the abc
Simply add the 13 on both sides and it will be in proper form.
did you do what @Lulu and @qpHalcy0n said? you need to get your equation in standard form: \(\large ax^2+bx+x=0 \) so you can identify your coefficients to use in the quadratic formula...
omg this is so confusing
i'm assuming that's what you meant by doing it the "abc" way...
idk i guess ill just have to figure it out later i need to give my brain a break
i meant \(\large ax^2+bx+c=0 \)
5 ± 2 5 ± 5 ± 2 5 ± 3
thats not one of the choices
I believe the last problem you posted could be factored into a product of two binomials. This one does not factor that nicely. Sorry. So disregard that. ...Or I was thinking of another problem.
5 ± 2sqrt3 5 ± sqrt38 5 ± 2sqrt2 5 ± 3sqrt2
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