Question

How do you simplify?

Answer 1

\[x ^{2}+6x-16/3x \times6x-18/x ^{2}-x-2\]

Answer 2

could u draw it or write it in eqn form ?

Answer 3

I don't know how to..

Answer 4

\[\frac{x^2+6x-16}{3x}*\frac{6x-18}{x^3-x-2}\]
this is your question
right?

Answer 5

@sakigirl

Answer 6

3x^2-9x, not just 3x. My bad

Answer 7

ok
\[\frac{x^2+6x-16}{3x^2-9x}*\frac{6x-18}{x^2-x-2}\]
this is correct now?

Answer 8

yes

Answer 9

ok
factor
x^2+6x-16
x^2+8x-2x-16
x(x+8)-2(x+8)
(x+8)(x-2)

now factors the
x^2-x-2
x^2-2x+x-2
x(x-2)+1(x-2)
(x-2)(x+1)

are you fallowing this?

Answer 10

yes

Answer 11

so now put the factor at the respective place
\[\frac{(x+8)(x-2)}{3x^2-9x}*\frac{6x-18}{(x-2)(x+1)}\]
so the x-2 in numerator and denominator gets cancelled

Answer 12

now
write 6x-18 as 6(x-3)
and
3x^2-9x as 3x(x-3)
so it becomes
\[\frac{x+8}{3x(x-3)}*\frac{6(x-3)}{x+1}\]
this time x-3 from both numerator and denominator will gets cancelled

Answer 13

now it becomes
\[\frac{x+8}{3x}*\frac{6}{x+1}\]

Answer 14

can you do this from here ??

Answer 15

@sakigirl

Answer 16

Yes :)