Question

show your work for 2-(4/(x^2)) = -(2/x)

Answer 1

\[2-\frac{4}{x^{2}} = -\frac{2}{x}\]

\[\frac{2x^{2}-4}{x^{2}}=\frac{-2x}{x^{2}}\]...

x NOT equal to 0 so....

\[2x^{2}-4=-2\]

\[x^{2}+x-2=0\]...

solve the quadratic equation for x...

we get x=-2...x=1

Answer 2

why did you put x^2 after 2 in the beginning of the equation and x after -2 at the end of the equation?

Answer 3

and why did you make the x under -2 into x^2?

Answer 4

sry the third equation should be...
\[2x^{2}-4=-2x\....

as for you question.....multiply and divide by x......so as to make the denominator equal on both sides so we can cancel afterwards....

Answer 5

thank you!