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Mathematics 45 Online
OpenStudy (anonymous):

show your work for 2-(4/(x^2)) = -(2/x)

OpenStudy (anonymous):

\[2-\frac{4}{x^{2}} = -\frac{2}{x}\] \[\frac{2x^{2}-4}{x^{2}}=\frac{-2x}{x^{2}}\]... x NOT equal to 0 so.... \[2x^{2}-4=-2\] \[x^{2}+x-2=0\]... solve the quadratic equation for x... we get x=-2...x=1

OpenStudy (anonymous):

why did you put x^2 after 2 in the beginning of the equation and x after -2 at the end of the equation?

OpenStudy (anonymous):

and why did you make the x under -2 into x^2?

OpenStudy (anonymous):

sry the third equation should be... \[2x^{2}-4=-2x\.... as for you question.....multiply and divide by x......so as to make the denominator equal on both sides so we can cancel afterwards....

OpenStudy (anonymous):

thank you!

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