Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Given: x – (5 – 3x + 2) = 15 + 3x Prove: x = 22 attatchment below OPTIONS What are the missing justification steps, in order? Commutative Property of Addition, Combine Like Terms, Distributive Property Associative Property of Addition, Distributive Property, Multiplication Property of Equality Associative Property of Addition, Commutative Property of Addition, Distributive Property Associative Property of Addition, Distributive Property, Addition Property of Equality

OpenStudy (anonymous):

OpenStudy (anonymous):

this is hard :/

OpenStudy (anonymous):

No it is easy if you know all the properties...

OpenStudy (jiteshmeghwal9):

plug the value of x in the equation to prove it

OpenStudy (jiteshmeghwal9):

22-(5-3(22)+2)=15+3(22)

OpenStudy (anonymous):

Just wait @jiteshmeghwal9

OpenStudy (anonymous):

-1289=81?

OpenStudy (anonymous):

You have to find x.. Just suppose that 22 is not the answer for 10 minutes.. @Gretchen2013

OpenStudy (anonymous):

?

OpenStudy (karatechopper):

x – (5 – 3x + 2) = 15 + 3x <-- VERY SIMPLE equation. First we want to do distributive property. We want to distribute the negative sign to the (5-3x+2) So then the equation will become.. x-5+3x-2=15+3x Now that we have our new equation -> x-5+3x-2=15+3x Lets break it down a bit more, By combining like terms! We will combine our x's together. so.. x-5+3x-2=15+3x will become.. 4x-5-2=15+3x Now, that we have combined our x's on one side, let us also combine the simple numbers together. So.. 4x-5-2=15+3x will become.. 4x-7=15+3x Now that we have our new equation -> 4x-7=15+3x This will become very easy to solve! 4x-7=15+3x We can start by adding the 7 to both sides. 4x-7=15+3x +7 +7 ------------ 4x=22+3x now we will subtract 3x on both sides. 4x=22+3x -3x -3x ---------- x=22

OpenStudy (anonymous):

theanks for explaining! @karatechopper

OpenStudy (karatechopper):

Most welcome! @Gretchen2013

OpenStudy (karatechopper):

Hey i used Option D on here.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!