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Find the vertex of the quadratic equation: y = 2x2 + 8x − 4
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Do you know how to find the x coordinate of the vertex?
i dont think
If you have the general equation \[\Large ax^2+bx+c=0\] then the x coordinate of that vertex is \[\Large x = -\frac{b}{2a}\]
In the case of \(\Large y = 2x^2+8x-4\), we can see that a = 2, b = 8 and c = -4
Does that help?
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yeah kinda
So what do you get for the x coordinate of the vertex?
i got -2
good
Since x = -2 is the x coordinate of the vertex, you can find the y coordinate of the vertex by plugging in this x value. So... \(\Large y = 2x^2+8x-4\) \(\Large y = 2(-2)^2+8(-2)-4\) I'll let you finish
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okay i got (-2,-12)
you nailed it
thank you for your help
you're welcome
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