Question

Calculate Sin0
Its a right triangle We dont know the hypotonuse, but the Opposite is 6 and Adjcent is 7

Answer 1

find hypotenuse using pythagoras
= sqrt(6^2 + 7^2)

then sin O = opposite / hypotenuse

Answer 2

you have opposite = 7 in your diagram but opposite = 6 in your question

Answer 3

Drawing is correct

Answer 4

ok - so sin O = 7 / (sqrt(6^2 + 7^2)

Answer 5

can you calculate this?

Answer 6

I got the answer! thank you! Does it work that way for all of he problems? For example:
Calculate Cos0

Answer 7

yup cos O = adjacent / hypotenuse = 6 / hypotenuse

have you heard of the memory aid SOH-CAH-TOA?

Answer 8

I've heard of it.. but dont get it...
So how do I set up the problem for Cos0 and Tan0

Answer 9

you should use x if you cannot type \(\theta\). 0 looks like zero

another way to do this is use tan x = opp/adj to find x, then do sin x or cos x

Answer 10

cos O is as i mentioned and tan O = opposite/adjacent = 7/6

Answer 11

If you want more on this, you can watch
http://www.khanacademy.org/math/trigonometry/v/basic-trigonometry

Answer 12

so its 6/9.22 now how do I do COS

Answer 13

cos x= 6/9.22= 0.65

Answer 14

maybe the video will make this clear.