Question

multiple choice algebra 2 pleaseee !

Answer 1

ya....question????

Answer 2

x-3y=-6
x+6=3y
(x+6)/3=y

Answer 3

its not showing up the way i type it

Answer 4

solve for y in the first equation,. x – 3y = –6 2x – 7y = 10
(x + 2, x + 6, –x + 2, x + 2)

Answer 5

2x+y=11
y=11-2x
=-2x+11

Answer 6

this was second question

Answer 7

thankyou so much :)

Answer 8

What is the value of y in the solution to the following system of equations?

5x – 3y = –3,
2x – 6y = –6

( –1,

0 ,

1,

2 ,)

Answer 9

mutiply first equation by 2 and second equation by 5:;

10x-6y=-6............(1)
10x-30y=-30........(2)
subtract (2) from (1):
24y=24
y=1

Answer 10

nice explanation thanks :) do u wanna help me with the other 2 too?

Answer 11

ok...sure

Answer 12

this one is kinda tough for me, it involves fractions lol
In the below system, solve for y in the first equation.

x – 3y = –6
2x – 7y = 10

(x + 2,

x + 6 ,

–x + 2 ,

x + 2 ,)

Answer 13

x+6=3y
so y=(x+6)/3

Answer 14

the answer choices are wrong. they are- ( 1/3 x+2, 1/3 x+6, -x+2, -1/3 x+2)

Answer 15

1/3 x+6 then?

Answer 16

ya...

Answer 17

thanks! this one i think its no solutions but im not sure.
Use the substitution method to solve the following system of equations.

3x – y = 2
6x – 2y = 4

(1, 1)

(–1, –5)

No Solutions

Infinitely Many Solutions

Answer 18

you there?

Answer 19

from 1st equation::
y=3x-2

put the value of y in second equation:
6x-2(3x-2)=4
6x-6x+4=4
4=4 which is true

so infinitely many solutions

Answer 20

oh okay thanks for all your help!

Answer 21

wait

Answer 22

let me check last on last one

Answer 23

no its right
infintely many solutions.......

Answer 24

any other

Answer 25

i have some that are a little more difficult. the have 3 variables.
The following system is solved by substitution. Which expression is substituted for z in the second and third equations?

x + 5y – z = 6
3x – y – 2z = 4
3x – 2y + 3z = 13

( x + 5y + 6

x + 5y – 6

–x – 5y + 6

–x – 5y – 6 )

Answer 26

from 1st...
x+5y-z=6
x+5y-6=z
so ....z=x+5y-6

Answer 27

:) thanks
Eliminate the “z” variable in the last two equations by finding opposite coefficients and adding. What is the resulting equation?

x + 3y + 2z = –16
2x – y + 2z = –15
2x – 2y – z = 1

(4x – 3y = –14

4x + y = –14

6x + 5y = 13

6x – 5y = –13 )