How do you prove that the diagonals of the square bisect the interior angles ?
and this is the picture with the question. If you can explain please do :)
Well, the diagonals are equal, and they bisect each other, right?
It must be in a proof kind of form..
The diagonals are equal, bisect each other, and intersect at 90 degrees. That is a fact for squares. Now, the diagonals form isosceles triangles with 45 degree base angles. Since 45 is half of 90, that proves that the diagonals bisect the interior angles.
Which branch of math are you studying? Geometry or Calculus or Vectors... Proofs depend on that... let me know
Geometry proofs @bhaweshwebmaster
As the others said, draw one diagonal on the square. It forms two isosceles triangles. The third angle for each is the corner of the square so equals 90. So the angles formed where the diagonal meets the square are 45. Alternatively by rotational symmetry you can see that the two angles where the diagonal comes to a vertex are equal.
Thanx!
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