Question

PLEASE HELP!!!

Answer 1

Is 98 correct?

Answer 2

You did like this no??

Let the angle be A

Let the whole length be x

So width of river is x - 49..

\[\tan(A) = \frac{x}{93}\]

To upper right triangle:

\[\tan(A) = \frac{x-49}{62}\]

Just equate them now..

Answer 3

93 62
-----=----
49+x x
That's what I did

Answer 4

93x=3038+62x
31x=3038
x=98

Answer 5

\[\frac{x}{93} = \frac{x-49}{62} \implies 62x = 93x - 93 \cdot 49 \implies 93 \times 49 = 31x \implies x = 147\]

Now:

\((x - 49)\) is the width of river:

so:

\(147 - 49 = 98\)

Answer 6

You are also right you can do it on your way too..

Nothing wrong in that..

But I show you what I let for each thing: