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Mathematics 11 Online
OpenStudy (anonymous):

check my work pleaseee for factoring

OpenStudy (anonymous):

OpenStudy (anonymous):

rationals* not factoring

OpenStudy (anonymous):

i think it's just your missing parenthesis....

OpenStudy (anonymous):

no, i just did it i get the same answer

OpenStudy (anonymous):

-2 , -5/7 is the correct answer to \(\large 7x^2+19x+10=0 \)... so what's the problem?

OpenStudy (anonymous):

that's not what im getting i just put it there by using the quadratic function on my calc

OpenStudy (anonymous):

how are u solving that quadratic?

OpenStudy (anonymous):

factoring?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

well since 7 is prime you know that has to be the first term in one of the binomials... (7x + )(x + ) = \(\large 7x^2+19x + 10 \) now just play around with the factors of 10 that will give you 19x in the middle term of the trinomial...

OpenStudy (anonymous):

14 and 5 are the factors

OpenStudy (anonymous):

but what do you do with the coeff ?

OpenStudy (anonymous):

14 is not a factor of 10

OpenStudy (anonymous):

can you list all the factors of 10 for me?

OpenStudy (anonymous):

it's -2

OpenStudy (anonymous):

-2 will give you zero

OpenStudy (anonymous):

is that an answer to one of my questions?

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

what what are you asking me, im confused

OpenStudy (anonymous):

you need to figure out what goes in the ???: (7x + ???)(x + ??) = \(\large 7x^2+19x+10 \) and i said you need to play around with the factors of 10.... my question is... what are the factors of 10?

OpenStudy (anonymous):

1,2,5,10

OpenStudy (anonymous):

ok... good... can we agree that 1 and 10 will not work here?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

no, we cannot agree... or no, it won't work?

OpenStudy (anonymous):

no 1 and 10 wont work

OpenStudy (anonymous):

ok... it's the 2 and 5 we're concerned with... which gives a correct expansion (first or second one?): (7x + 2)(x + 5) or (7x + 5)(x + 2) of \(\large 7x^2+19x+10 \) ???

OpenStudy (anonymous):

(7x + 5)(x + 2)

OpenStudy (anonymous):

ok.... there's your factorization....

OpenStudy (anonymous):

thankyouu so very much !

OpenStudy (anonymous):

yw...:)

OpenStudy (anonymous):

since you already knew your answer (from your calculator), you could actually work backwards to get your factorization: since you know -2 was a solution, then (x + 2) has to be a factor... do that with the other solution you'll get (7x + 5)....

OpenStudy (anonymous):

ohhh ! yeah i didnt think of that, that would have been much easier

OpenStudy (anonymous):

i didn't wanna say anything because i'm a masochist!

OpenStudy (anonymous):

...:)

OpenStudy (anonymous):

hahaha !

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