Question

solve the following systems of equations by applying the method of Gauss:

-2x-y+z=-4
3x+y-2z=6
2x+y+z=6

Answer 1

@Muskan why do u find this difficult?

Answer 2

i dont understand this equation
the method of gauss

Answer 3

solve 2 eqns to remove a variable ,solve the new eqn with the 3rd eqn

Answer 4

I get no good answer

Answer 5

u can also use a matrix and row-reduce it
i think this is what u r supposed to do!

Answer 6

ya u can indeed use matrices

Answer 7

AX=B

Answer 8

What I like to do when solving linear systems is to label my equations. For these lets label them from top to bottom, 1, 2, and 3.
I see that if we add 1+2 or 1+3, we can eliminate a variable and create a new equation 4.

Want to first give that a try?

Answer 9

@agentc0re ME 2 :p

Answer 10

i was tried..

Answer 11

@AravindG It's the best way to keep track of things, don't ya think? :D great minds think alike.

Answer 12

how can i solve ...

Answer 13

Well what happens when you make two new equations by adding 1+2 and 1+3 like i suggested? call these new equations 4 and 5.

Answer 14

u can solve when u make an honest attempt!!

Answer 15

Come on @Muskan if we solve this for u it won't do u any good
do what @agentc0re suggested and tell us what u got

Answer 16

k..

Answer 17

hey u have three equation and three unknown variable ! just find them a;;

Answer 18

What did you get when you do what i suggested? Post your two new equations and we can go from there! :D

Answer 19

@Muskan ?

Answer 20

wait 2 min plz

Answer 21

so?

Answer 22

first equ: -2x-y+z=4
second equ: 3x+y-2z=6
.................................
-x -z=2

first equ: -2x-y+z=4
third equ: 2x+y+z=6
.............................
2z=2

first equ: -2x-y+z=4 > -2*3-y+1=-4 > y=-4-1+6 > y=1
second equ: -x -z=2 > -x-1=2 > x=3
third equ: 2z=2 >z=2/2> z=1

y=1
x=3
z=1

Answer 23

the sign of x is wrong

Answer 24

-x=1+2> -x=3

Answer 25

right -x=3 then x=-3

Answer 26

okk

Answer 27

u have to recompute the value of y

Answer 28

but..still is bad..

Answer 29

eres española?
según tu perfil estudias en Linares

Answer 30

si estoy en espana

Answer 31

yo soy de Bolivia

Answer 32

aa bien

Answer 33

hablar ingles muy bien

Answer 34

tu solución es x=-3, y=11 y z=1

Answer 35

como y=11

Answer 36

te dije que tenías que calcular de nuevo el valor de y

Answer 37

first equ: -2x-y+z=4 > -2*3-y+1=-4 > y=-4-1+6 > y=1

yo hecho asi..
donde esta fallo

Answer 38

tenías z=1 pero x=3 (que no era correcto)
lo correcto ex z=1 y x=-3 entonces
-2x-y+z=4
se convierte en
-2(-3)-y+1=4
de donde y=4-1-6=-3

Answer 39

pero no es y=11
es y=-3

Answer 40

lo siento cometí un error
z=1
x=3
y=-1

Answer 41

ahora
z=1
y=-3
x=-3
es correcto

Answer 42

en lo que escribiste arriba -x-z=2
el signo de x es incorrecto
debería ser x-z=2 de donde x=3 (pues z=1)

Answer 43

aah vale

Answer 44

entonces -2x-y+z=-4 se convierte en
-2(3)-y+1=-4
de donde -y=-4-1+6=1 de donde y=-1

Answer 45

man.wat language is this!!!!!! strange!

Answer 46

yuhuuuuuuuuuuuuu
I gottttt it....

Answer 47

@Yahoo! is spanish

Answer 48

u r frm Spain

Answer 49

i thought u are frm PAK

Answer 50

m 4rom pak
but i live in spain

Answer 51

oh.......thats Fine!

Answer 52

m happy
i got my ans...

Answer 53

i think u have done well...))

Answer 54

buen trabajo @Muskan !

Answer 55

gracias :))

Answer 56

Adios, y cuídate

Answer 57

hasta luego..

Answer 58

igualmente